Answer : 3 21/38 Explanation : Answer: C) 21/38 Explanation: n(S) = C220 = 190 n(E) = C215 = 105 Therefore, P(E) = 105/190 = 21/38

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A box contains 5 detective and 15 non-detective bulbs. Two bulbs are chosen at random. Find the probability that both the bulbs are non-defective.

Answer : 3 21/38 Explanation : Answer: C) 21/38 Explanation: n(S) = C220 = 190 n(E) = C215 = 105 Therefore, P(E) = 105/190 = 21/38

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