Answer : 2 112/495 Explanation : Answer: B) 112/495 Explanation: nS= C4 12=495 nE= C28×C14=112 ∴P(E)=112495

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A bag contains 8 red and 4 green balls. Find the probability that two balls are red and one ball is green when three balls are drawn at random.

Answer : 2 112/495 Explanation : Answer: B) 112/495 Explanation: nS= C4 12=495 nE= C28×C14=112 ∴P(E)=112495

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